The first data set (arranged in order) is
5 5 8 10 [15 15] 15 22 28 32
|
|
Measurement |
(Measurement)2 |
|---|---|---|
|
|
5 |
25 |
|
|
5 |
25 |
|
|
8 |
64 |
|
|
10 |
100 |
|
|
15 |
225 |
|
|
15 |
225 |
|
|
15 |
225 |
|
|
22 |
484 |
|
|
28 |
784 |
|
|
32 |
1024 |
|
Totals |
∑x = 155 |
∑x2 = 3181 |
(∑x)2 = 24025
(∑x)2 ⁄ n = 2402.5
n − 1 = 9
So, s = √( ( 3181 − 2402.5 ) ⁄ 9 ) = 9.30
Second data set
Since the first data set has a mean., mode and median very close to one another, it is likely to have a normal distribution.